In class we've been working on loop statements and as part of my homework (this is the only part I don't have done) is to be able to take the odd numbers within a number (so say the number is 32677, take the odd numbers) and add them together (so it would be 17). Maybe I'm just having a brain fart, but I just can't think of how to write this code.

 

Thanks!

Last time you posted, I showed you how to isolate the last digit in an integer. So you want to remove the last digit from the integer each iteration, check if it's odd, and add it to the sum if it is.

 

while(input > 0){
t = input%10;
if(t%2==1){sum+=t;}
input /= 10;
}

 

That's the necessary part in C++. You should be able to figure it out from there.

That is actually a neat way of doing it, Meredith.

 

The Java equivalent of the above:

int number=1234567,sum=0,trimmed;
while(number!=0){
   sum+=(trimmed=number%10)%2==1?trimmed:0;
   number/=10;
}
System.out.println(sum);

 

Isn't a whole lot different then yours. :P.

 

 

He could, however, use Scanner in which his entire project is only a few lines:

int sum=0,trimmed;
Scanner number=new Scanner(System.in).useDelimiter("");  
System.out.print("Enter an integer: ");  
while(number.hasNextInt()){sum+=(trimmed=number.nextInt())%2==1?trimmed:0;}   
System.out.println("The sum of the odd integers is: "+sum);

Gets the input and outputs the sum. :P.

Thanks for the help guys, I appreciate it!