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Algebra problem

Featured Replies

Indy, your solution is incorrect, you can't cancel the y's like that in the first step. They're not multiplicative.

 

 

 

I'll post mine up in a minute once i've typed it out.

 

 

 

solutionor4.jpg

 

 

 

Fairly self explanatory.

 

 

 

Yes you can. And we got the same answer, so it is right. (y^2-y)/y can be simplified to (y-1)/1, like I have.

q8tsigindy500fan.jpg

indy500fanan9.jpg

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algebraym6gt8.png

 

algebraym6gt8.acd5e3bc70.jpg

 

 

 

This is really not a hard problem. I shouldn't have to explain this to anyone who has taken algebra before. People don't seem to get it though, so I separated it into 6 steps and will explain anything that you think is wrong.

 

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Indy, your solution is incorrect, you can't cancel the y's like that in the first step. They're not multiplicative.

 

 

 

I'll post mine up in a minute once i've typed it out.

 

 

 

solutionor4.jpg

 

 

 

Fairly self explanatory.

[/hide]

 

 

 

Assassin, your answer is the same as Indy's; however, your answer is expressed in a different way. If you split the numerator and cancel the x's, you will get the exact same answer. Both of you are correct. You both just did it in slightly different steps.

 

 

 

Indy's first step is algebraically acceptable. He factored a y out of the numerator and denominator of the left fraction. This left a y/y which cancels out (y/y = 1).

 

 

 

 

 

Edit: Indy beat me to it.

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