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Smithing steel bars/cannonballs..


forestfrolic

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My current method is taking out 18 coal and 9 iron ore.. while having the ammo mould in my inventory. I smelt EDIT:9 steel bars, then I make the bars into cannonballs.

 

 

 

Would it be quicker to bank the steel bars? And then later bring a full inventory of them and create cannonballs?

 

 

 

I'm just looking for the quickest way. What do you do?

Nemo vir est qui mundum non reddat meliorem..

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Smelting bars and cannonballs together:

 

 

 

18 coal + 9 iron ore + mould in inventory.

 

18 coal + 9 iron ore = 9 steel bars

 

9 steel bars x 4 cannonballs = 36 cannonballs

 

This gives you 36 cannonballs in per trip.

 

 

 

 

 

Smelting bars, banking them and then smelting cannonballs later:

 

 

 

18 coal + 9 iron ore in inventory.

 

18 coal + 9 iron ore = 9 steel bars

 

--bank--

 

27 steel bars + mould in inventory

 

27 steel bars x 4 cannonballs = 108 cannonballs

 

 

 

To get 27 steel bars you will have to do 27 / 9 = 3 bar smelting trips.

 

That means you will need 3 trips to smelt bars, plus 1 trip to smelt the cannonballs.

 

This gives you 108 cannonballs in four trips, that is an average of 108 / 4 = 27 per trip.

 

 

 

 

 

You can see that smelting the cannonballs right away results in 9 cannonballs extra per trip so you should definitely keep doing what you do now.

 

 

 

Example with 1000 steel bars:

 

 

 

Smelting bars and cannonballs together:

 

 

 

9 bars per trip.

 

1000 / 9 = 111.111 (round to 112)

 

That is a total of 112 trips.

 

 

 

 

 

Smelting bars, banking them and then smelting cannonballs later:

 

 

 

9 bars per trip, plus an extra trip every 3 bar smelting trips to smelt the cannonballs.

 

1000 / 9 = 111.111 (round to 112)

 

112 + ( 111.111 / 3 ) = 149.037 (round to 150)

 

That is a total of 150 trips.

 

 

 

112 trips or 150 trips... I know my choice... :P

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Smelting bars and cannonballs together:

 

 

 

18 coal + 9 iron ore + mould in inventory.

 

18 coal + 9 iron ore = 9 steel bars

 

9 steel bars x 4 cannonballs = 36 cannonballs

 

This gives you 36 cannonballs in per trip.

 

 

 

 

 

Smelting bars, banking them and then smelting cannonballs later:

 

 

 

18 coal + 9 iron ore in inventory.

 

18 coal + 9 iron ore = 9 steel bars

 

--bank--

 

27 steel bars + mould in inventory

 

27 steel bars x 4 cannonballs = 108 cannonballs

 

 

 

To get 27 steel bars you will have to do 27 / 9 = 3 bar smelting trips.

 

That means you will need 3 trips to smelt bars, plus 1 trip to smelt the cannonballs.

 

This gives you 108 cannonballs in four trips, that is an average of 108 / 4 = 27 per trip.

 

 

 

 

 

You can see that smelting the cannonballs right away results in 9 cannonballs extra per trip so you should definitely keep doing what you do now.

 

 

 

Example with 1000 steel bars:

 

 

 

Smelting bars and cannonballs together:

 

 

 

9 bars per trip.

 

1000 / 9 = 111.111 (round to 112)

 

That is a total of 112 trips.

 

 

 

 

 

Smelting bars, banking them and then smelting cannonballs later:

 

 

 

9 bars per trip, plus an extra trip every 3 bar smelting trips to smelt the cannonballs.

 

1000 / 9 = 111.111 (round to 112)

 

112 + ( 111.111 / 3 ) = 149.037 (round to 150)

 

That is a total of 150 trips.

 

 

 

112 trips or 150 trips... I know my choice... :P

 

 

 

Damn. Thank you! I was just too lazy to do the math. And you just did it for a complete stranger. Thanks.

Nemo vir est qui mundum non reddat meliorem..

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