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math help pl0x


katsuro0

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how do you solve for x when:

 

 

 

x^3 + 216 = 0

 

 

 

the answer should be -6, 3 + 3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3i, 3 - 3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3i

 

the checkmark is a root sign

 

 

 

 

 

i know how to get the -6 cause x^3+216=0 factors into (x+6)(x^2-6x+36)=0

 

 

 

but i have no idea how im supposed to get the last two parts (except from looking in the back of the book...but i have to show work, and there's like 15 problems similar to this)

 

 

 

so help = appreciated. if i figure out how to do one of these, i can get the rest

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no, the quadratic formula is only for quadratics.

 

quadratics are ax^2+bx+c=0

 

that equation has an x^3

 

I would use synthetic division.

I used to have a link to my school's project to provide fresh water to a Kenyan Village, but the sig police changed the link to say something, which, if followed, leads to an "ahem" adult website. Let me ask you. Which do you think is worse?

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I would still use synthetic division in the first place. makes life so much easier \'

I used to have a link to my school's project to provide fresh water to a Kenyan Village, but the sig police changed the link to say something, which, if followed, leads to an "ahem" adult website. Let me ask you. Which do you think is worse?

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Guest XplsvBam
after you factor, you have a quadratic equation. the answer came out right so ty xpls for reminding me of that annoying formula lol
no problem, just helping you help yourself.
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I should know this, but it's been about 4 years since I took Algebra 2.

 

 

 

 

 

Btw... this is the part of math that you will hate most lol

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And in case you hadn't seen the factors:

 

 

 

x^3 = -216

 

 

 

(a+bi)^3 = -216

 

 

 

1) Real part: a^3-3ab^2 = -216

 

AND

 

2) Imaginary part: 3ba^2-b^3 = 0

 

 

 

From 2)

 

3) b^3 = 3ba^2

 

b^2 = 3a^2

 

 

 

From 1) and 3)

 

4) a^3-3ab^2 = -216

 

a^3-9a^3 = -216

 

8a^3=216

 

a^3=27

 

a=3

 

 

 

From 3) and 4)

 

b^2 = 3a^2

 

b = 3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3 OR -3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3

 

 

 

Thus 3+3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3i and 3-3ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡3i are solutions too. ^^

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