stan18 Posted November 12, 2005 Share Posted November 12, 2005 Alright, im writing a study guide for my friends/classmates about Chem, or specifically, the electronic structure of atoms. Our teacher gave out sample test questions, and one was especially a pain. Our teacher gave these out before our weekend, so we never got the answers, and i wanted to include it in my guide. Apparently, someone also got the same answer as me and asked the teacher, but he said it was incorrect. Heres the problem: Hypothetically, How many electrons can have N=9 and mL=0. That is, when the principle number is 9 and the mL is the magnetic quantum number. i figured it was 18, since the L (azimuthal) numbers included 0, 1, 2, 3, 4, 5, 6, 7, and 8(possible L = n-1, including 0), and the possible combinations all had 2 electrons in each orbital type with 0 as a possible number since they have opposite spins later on. The total number of electrons in the 9th shell is 162 (2n^2) and if i add all the possible quantum numbers up, it adds up to 162, which also includes the 18 quantum numbers with mL = 0. [rant] My chem teacher is horrible. No one knows whats going on, and he expects us to read from the textbook to find all the stuff we need for the chapter. And hes a smart-wagon, so when we are unsure about small things he says its obvious and easy, and we should know it, and doesn't answer the question. BTW, he taught the lesson on shells and subshells on the school day before the test, which was wednesday. AND he didn't tell us it was about shells and subshells, so no one got it. [/rant] Any help would be great, thanks ;) p.s. this is 10th grade Chem 1H material. I probably won't understand anything college level :P Link to comment Share on other sites More sharing options...
Peter Posted November 12, 2005 Share Posted November 12, 2005 Sorry, but I took honors chemistry and I have hardly any idea what you're talking about, except for orbitals and electrons. Might want to check the internet for that one. Link to comment Share on other sites More sharing options...
Not Posted November 12, 2005 Share Posted November 12, 2005 The Question is refering to Pauli Exclusion Principle, I'm not exactly what the answer is but this is what we are going over in My College Chem class right now. Edit: Here is the answer: 1. For the given n of 9 the range of L is from 0-8 2. For each of the L values there are two electrons with a ml of 0. The range of L is 0-8 so that is 9 orbitals, each orbital has two electrons so the answer is 9x2=18. Link to comment Share on other sites More sharing options...
weezcake Posted November 12, 2005 Share Posted November 12, 2005 The Question is refering to Pauli Exclusion Principle, I'm not exactly what the answer is but this is what we are going over in My College Chem class right now. Edit: Here is the answer: 1. For the given n of 9 the range of L is from 0-8 2. For each of the L values there are two electrons with a ml of 0. The range of L is 0-8 so that is 9 orbitals, each orbital has two electrons so the answer is 9x2=18. I'm doing the exact same thing in my college chem class. I believe that is the answer, and I second it. :D ==================================Retired tip.it moderator.Teaching and inspiring. Link to comment Share on other sites More sharing options...
stan18 Posted November 12, 2005 Author Share Posted November 12, 2005 The Question is refering to Pauli Exclusion Principle, I'm not exactly what the answer is but this is what we are going over in My College Chem class right now. Edit: Here is the answer: 1. For the given n of 9 the range of L is from 0-8 2. For each of the L values there are two electrons with a ml of 0. The range of L is 0-8 so that is 9 orbitals, each orbital has two electrons so the answer is 9x2=18. I'm doing the exact same thing in my college chem class. I believe that is the answer, and I second it. :D sweet, thanks for all your help :D Link to comment Share on other sites More sharing options...
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