Well I do have a formula that's more accurate now, but you're not going to like it. Here it goes: Assuming a=your initial cashpile, b=percent profit from flipping (1.02 if you want to keep to the previous example), c=profit per cycle (outside of flipping, to keep it simple, lets say from 2 hours of frost drags), n=number of cycles you're looking at. ab^n + cb^(n-1) + cb^(n-2) + cb^(n-3) ... + cb^(n-n) I believe this takes into account that you will not use your first frost dragon profit to flip, as well. So for example, if we work in the millions, a=1 (1m initial money), b=1.02, c=6 (6m profit per flip). Now if we take n=4: (1)(1.02)^4 + (6)(1.02)^3 + (6)(1.02)^2 + (6)(1.02)^1 + (6)(1.02)^0 = 25.8 (25.8m total cashpile at the end). Note that last term simplifies down to just +6, because you get the profit from those 2 hours of frost dragons, but not from flipping it. As you can see, this formula gets crazy tedious with a lot of cycles. An exact formula for a situation like this is exceedingly hard to compute because it involves an iterative differential equation that would need to be solved on a case-by-case basis. Yours is a relatively good estimate for low n, but with higher n, the error becomes very significant.