How do leech curses work?

[king_muumuu]

I am thinking of switching to Ancient curses for the Armadyl boss, so I can use Leech defence on him. I have used it in the past but I still don't grasp how it works.

 

To make it easier to understand, let's say both me and my opponent have a natural defence level of 100 (I know, it's impossible, but bear with me). Now, Leech defence starts reducing the opponent's def by 10% and increasing mine by 5%, and over time it can drain his 25% and boost mine 10%. So if I fight sufficiently long with the opponent, by defence will be 110 while his is now 75. Now my opponent dies and instantly respawns. If I engage battle with him, my defense will still be 110, but will his start out at 75 from the beggining of the fight or will it be 100 and will decrease slowly as I fight?

In other words, is the defence drain dependent on how good my own defense bonus currently is, or how long I have fought the opponent for, thus resetting for each new enemy?

 

Thanks.

[xpx]

It's more than likely that your opponents defense always starts at 100 when you first attack him, regardless of your boosted defense level, but there is really no way to know for sure.

[king_muumuu]

Hmm I asked a friend to come help me test this in friendly clan wars. While my boost was 10% and his def -17%, I killed him, he came back instantly and his def did not start out at -17%, but rather -10%. That way it is dependent on the length of the battle for each individual opponent. Bah.

[Quyneax]

Hmm I asked a friend to come help me test this in friendly clan wars. While my boost was 10% and his def -17%, I killed him, he came back instantly and his def did not start out at -17%, but rather -10%. That way it is dependent on the length of the battle for each individual opponent. Bah.

Thanks for finding out :thumbup:.