Auror

yh, pls tell us

Not a good idea.

Oh and Aussie, I multiplied the denominators together, then the numerators together, apparently that got me the wrong answer.

Those are the kind of people we're looking for! ~ McDonalds

But: P(BBW) P(BWB) P(WBB) P(WWB) P(WBW) P(BWW) I will basically get 6 (probably) different answers. What do I do then? Just + them? h yeah, I also forgot to mention that the right answer is 5/6. 6/7 is wrong :/ EDIT: [bleep], you made a mistake, you calculated it right, but the answer is wrong, lol. Check your last sentence. EDIT2: I did it the tree way, got 20/27...

i asked my teacher, who gave us these exercises, how to do the probability exercise I asked you here. She told me to write down all possible combinations, but that didn't make sense in my eyes, because there were a total of 9 balls ( 4 black and 5 white),and I was to pick up only three balls, and because a certain ball is not individual, It felt way too abstract for me. Not sure if you understood, but that is what I was thinking.

"Ok. It is quite obviously a circle. Don't ask me why I know it, I just [bleep]ing well do. The circle has radius 5, and centre (1,3)" holy shit, why the [bleep] couldn't I have thought of that. I tried to use the distance-between-two-points formula... what the [bleep] am I doing in college. But yeah, thank you very much for helping me. I really like the way you sware :) You'll become a great teacher.

and the Overly Attached Girlfriend :)

Hmm... Thank you very much man. I see you didn't bother to think about the vector question, but it doesn't matter, because vectors are completely gay.

Onneks Olkoon Suomi :)! Gratz Suomi! :)

Onneks Olkoon :)

you smell'd dat word from 4 forums away, only true gaybois can do dat

Because of the xmas and new year spirit, imma let you know that you are not alone :) <33 i watch this blog everytime, believe me

Congratulations Kaida! And thank you for the two warnings! <3

1) f(x) = 2x + 3, and a point (1,3) Which points of f(x) are 5 away of the point (1,3). 2) There are 4 black balls and 5 white balls. You pick up 3 balls. What is the probability of having two different coloured balls.

Our friend Mishy doing a scamming FC? Sounds a bit Fishy. teeheehee

So, you think that Jagex should remove the 5k cw game req?

There are many requirements which can be considered as meaningless and useless, but they are requirements now, and we have to deal with them. They will never ever change them, so talking about them is useless and meaningless too. And no, the 5K CW game req is not an excuse to bot, so straighten up and either play or loaf them legitly or gtfo. (Not directed at Ginger Warrior, just to the public)

nude pics of who. Aten? Eww, yes, warn us, please.

Ginger Warrior, it's not like that the only way to get those 5k cw games is to loaf them. One could actually play 5k CW games, so, then it would require = attention, effort, and skill in order to win games. Would 5k CW games then be an achievement?

Go Gunnar, Go! :P

Thank you very much :). Is there a concrete site which contains all maths rules?

bro, could u possible tell me all the rules which apply to absolute value equation/inequality? You know, in a super briefy way

One of these banned players told me some names of some players, who have botted 5k cw games, or are still botting, and which are still not banned. Also, talking about how meaningless the 5k cw game requirement is is too late now. It's not like that Jagex is going to remove that requirement anymore, that would be unfair towards those people, who have legitly loafed those games. And, let us be honest, without the 5k CW Game req the Trimmed Comp wouldn't be any special because it wouldn't be that rare anymore.

Journalism? That's a cool occupation/job, but lemme give one advice: Always stay unbiased. :)