The strategy for figuring that out applies to all types of games and all types of statistics, whether its 60x2 or a different game. [hide=More complicated example using the same technique.] Take for instance 7-hi-lo. The house rolls two six sided dice, and the result is the two dice added up. You have the option of betting the dice will roll lower than 7, 7, or higher than 7. The house pays 2:1 if you bet higher or lower, and pays 5:1 if you bet 7. What is your expected long run return? This game isn't as simple as 60x2, but the strategy for computing it is the same. Say you bet lower than 7, how do you compute your long run return. When you roll two dice, there are 36 unique ways the dice can roll - the first dice could roll 1, the second could roll 1. The first could roll 1, the second could roll 2 and so on. The result of the dice can be 2-12, so what's the probability the roll is lower than 7? Its the same as saying the roll is either a 2, 3, 4, 5, or 6. The probability of a 2 is 1 in 36, the same as saying you must roll a 1 and a 1. The probability of a 3 is 2 in 36, you can roll 1 and 2 or 2 and 1. The probability of lower than 7 is P(2) + P(3) + P(4) + P(5) + P(6), or (1,1) + (1,2) + (2,1) + (3,1) + (2,2) + (1,3) + ... + (1,5) or 15 / 36. If the house pays 2:1, you'll win 30/36 of your money back, or you lose 1/6 of your money bet in the long run. [/hide]