dymed Posted February 27, 2006 Share Posted February 27, 2006 dymed: 2 if there are only 2, then the probablility is 50% that they share, 50% they dont. If I'm wrong, then i guess im the kind of person who will argue, if im right, good try Actually...you're completely wrong. But nice try. 2 isn't even the intuitive answer. Think about what you just said. The probability of two people sharing the same birthday is not 1/2. It would be 1/2 if there were only two days in the year. However, there are 365 days in the year, meaning the probability of two people having the same birthday is 1/365. :wink: Link to comment Share on other sites More sharing options...
runesmithie Posted February 27, 2006 Share Posted February 27, 2006 If a train leaves New York for San Francisco at a speed of 75 MPH and has 1100 scoops of ice cream in its freezer and the freezer breaks, and the scoops are melting at a rate of 3 scoops every 3 minutes, how many scoops will be left when the train reaches it destination? No scoops are left! I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
Birdboy60 Posted March 2, 2006 Author Share Posted March 2, 2006 Think about what you just said. The probability of two people sharing the same birthday is not 1/2. It would be 1/2 if there were only two days in the year. However, there are 365 days in the year, meaning the probability of two people having the same birthday is 1/365. :wink: Well, jeez, But if there are only 2 ppl, then the chances are exactly half. It is due to that there are 2 ppl, and 2 possible outcomes. They either share the same birthday, or they dont. so if there are 2 ppl and 2 possible outcomes, it is 50/50. Man I hate probablities. Fabricant: I'm assumming that Colint94 is thinking we know the distance of the rail-lines between NY and SF and that we work that out ourself. Another problem is that he never says how many stops it takes, and if it does stop if the freezer is fixed. So we can't answer due to a shortage of information. Also, I understand your solution, but mine makes sense too, don't they? lol Wow, this got slightly popular now didn't it? Anymore? Link to comment Share on other sites More sharing options...
runesmithie Posted March 2, 2006 Share Posted March 2, 2006 Think about what you just said. The probability of two people sharing the same birthday is not 1/2. It would be 1/2 if there were only two days in the year. However, there are 365 days in the year, meaning the probability of two people having the same birthday is 1/365. :wink: Well, jeez, But if there are only 2 ppl, then the chances are exactly half. It is due to that there are 2 ppl, and 2 possible outcomes. They either share the same birthday, or they dont. so if there are 2 ppl and 2 possible outcomes, it is 50/50. Man I hate probablities. Fabricant: I'm assumming that Colint94 is thinking we know the distance of the rail-lines between NY and SF and that we work that out ourself. Another problem is that he never says how many stops it takes, and if it does stop if the freezer is fixed. So we can't answer due to a shortage of information. Also, I understand your solution, but mine makes sense too, don't they? lol Wow, this got slightly popular now didn't it? Anymore? Actually the odds of them having the same birthday are lower than the odds against. And as to the ice cream problem, it doesn't matter unless the freezer is fixed or the distance is less than 1375 miles And since he didn't state the first and the second is very impossible they will have no scoops left I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
Corvus Posted March 8, 2006 Share Posted March 8, 2006 why doesn't any one guess on my last question Thanks to DrCue at DeviantArt for the signature source Link to comment Share on other sites More sharing options...
Fabricant Posted March 9, 2006 Share Posted March 9, 2006 wyvern, can you please tell us the language it is in? i tried french and this is what came up: you will help has rappler your quantity has many friendly doctors Dai jou bui! The full stop and comma are your friend....http://www.blogger.com/profile/31134299 Link to comment Share on other sites More sharing options...
Corvus Posted March 10, 2006 Share Posted March 10, 2006 it is in french but it has nothing to do with langages!!!! it is a pnmonic for something in math!!!! i will post the answer tommorow my time Thanks to DrCue at DeviantArt for the signature source Link to comment Share on other sites More sharing options...
soulman01 Posted March 10, 2006 Share Posted March 10, 2006 Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 2 ppl...Get twins :wink: Link to comment Share on other sites More sharing options...
runesmithie Posted March 10, 2006 Share Posted March 10, 2006 Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 2 ppl...Get twins :wink: Except that would be 100% Congratulations, you fail at trying to outsmart the system :P I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
Birdboy60 Posted March 10, 2006 Author Share Posted March 10, 2006 what does this mean: tu aideras a rappler ta quantite a beaucoup de docteurs amis Take Away And Replace The Quanity After Begining Division During Alegabra. I'm probably wrong but it kinda makes sense, and uses the first letters. Otherwise I'm clueless. Link to comment Share on other sites More sharing options...
Corvus Posted March 15, 2006 Share Posted March 15, 2006 e srry i have been busy recently e=2.7182818284 you were suposed to count the letters in each word Thanks to DrCue at DeviantArt for the signature source Link to comment Share on other sites More sharing options...
Blipo Posted March 15, 2006 Share Posted March 15, 2006 This one's a math "puzzle." The answer is very counter-intuitive and surprises pretty much everyone who hears it for the first time. And then there are those who will argue that the right answer is actually wrong, even when they have explicitly been shown the proof for it. Anyway, here it is. Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 23. Link to comment Share on other sites More sharing options...
runesmithie Posted March 15, 2006 Share Posted March 15, 2006 This one's a math "puzzle." The answer is very counter-intuitive and surprises pretty much everyone who hears it for the first time. And then there are those who will argue that the right answer is actually wrong, even when they have explicitly been shown the proof for it. Anyway, here it is. Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 23. Woot, a google user are you! :D I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
Blipo Posted March 15, 2006 Share Posted March 15, 2006 This one's a math "puzzle." The answer is very counter-intuitive and surprises pretty much everyone who hears it for the first time. And then there are those who will argue that the right answer is actually wrong, even when they have explicitly been shown the proof for it. Anyway, here it is. Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 23. Woot, a google user are you! :D Not really. We did this in math class last week. Link to comment Share on other sites More sharing options...
godsfearme Posted March 15, 2006 Share Posted March 15, 2006 So you only need 46 to the the thoertical probilty to get to one hundered. I will shoot down any one with my bitting wit, and sarcasm!What POSSIBLE reason would someone have to make a fake like that?Does he profit from faking a picture like that? Does it help him at all?Jesus Christ, stop being so suspicious. This is Tip.it for God's sake, not RuneHQ. -_- Link to comment Share on other sites More sharing options...
runesmithie Posted March 16, 2006 Share Posted March 16, 2006 So you only need 46 to the the thoertical probilty to get to one hundered. No, you need 365 for 100 :P I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
Not2Day1024 Posted March 19, 2006 Share Posted March 19, 2006 This one's a math "puzzle." The answer is very counter-intuitive and surprises pretty much everyone who hears it for the first time. And then there are those who will argue that the right answer is actually wrong, even when they have explicitly been shown the proof for it. Anyway, here it is. Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 23. Woot, a google user are you! :D Why post a question if you are going to flame the person who gets it right? Link to comment Share on other sites More sharing options...
runesmithie Posted March 19, 2006 Share Posted March 19, 2006 This one's a math "puzzle." The answer is very counter-intuitive and surprises pretty much everyone who hears it for the first time. And then there are those who will argue that the right answer is actually wrong, even when they have explicitly been shown the proof for it. Anyway, here it is. Ignoring all leap years, how many people would you have to put in a room so that the probability of having two people in the room share the same birthday is 1/2? 23. Woot, a google user are you! :D Why post a question if you are going to flame the person who gets it right? Wasn't me that posted it I just posted something! ^_^ to the terrorist...er... kirbybeam. Link to comment Share on other sites More sharing options...
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