Sp4de Posted July 20, 2006 Share Posted July 20, 2006 Sp4de I'm 99% possitive that 2nd one is completely incorrect. Yeah I figured, maybe I should make sure I can do this stuff before I try to explain. :shame: ÃÆââ¬Å¡Ãâï(ÃÆââ¬Å¡Ãâú_o)/ÃÆââ¬Å¡Ãâï Link to comment Share on other sites More sharing options...
Foooman Posted July 20, 2006 Share Posted July 20, 2006 this is regarding what he said ingame. 9x(sq) + 24x +16 (ax+B)(cx+d) is the answer. in this: a * c = 9 b * d = 16 (a * d) + (c * B) = 24 This means: a and c must multiply to equal 9. These choices are... 3,3 9,1 So: The answer is (3x_B)(3x_d) -or- (9x_B)(x_d) Now we know that b and d must multiply to equal 16. So b and d can be: 4,4 16,1 2,8 Now we have all choices of: (3x+4)(3x+4) (3x+16)(3x+1) (3x+2)(3x+8) (9x+4)(x+4) (9x+16)(x+1) (9x+2)(x+8) (9x+1)(x+16) (9x+8)(x+2) From this we can conclude: (3x+4)(3x+4) = 9x(sq) + 24x + 16 QED Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 20, 2006 Author Share Posted July 20, 2006 this is regarding what he said ingame. 9x(sq) + 24x +16 (ax+B)(cx+d) is the answer. in this: a * c = 9 b * d = 16 (a * d) + (c * B) = 24 This means: a and c must multiply to equal 9. These choices are... 3,3 9,1 So: The answer is (3x_B)(3x_d) -or- (9x_B)(x_d) Now we know that b and d must multiply to equal 16. So b and d can be: 4,4 16,1 2,8 Now we have all choices of: (3x+4)(3x+4) (3x+16)(3x+1) (3x+2)(3x+8) (9x+4)(x+4) (9x+16)(x+1) (9x+2)(x+8) (9x+1)(x+16) (9x+8)(x+2) From this we can conclude: (3x+4)(3x+4) = 9x(sq) + 24x + 16 QED ok from the problem b4, ths is waht i though you had to do. this is what i thought you had to do. Example 9x(sq) + 24x + 16 step 1. Find the two numbers that you can multiply to get 16 (4,4) (2,8) (16,1) to name a few step 2. Do 9 times 4, plus 4. Or 9 times 2 plus 8, and reversed and etc. ( do you get what im saying) Until you got to 24. so this isnt right? Click here to see my blog. Link to comment Share on other sites More sharing options...
mad4u689 Posted July 20, 2006 Share Posted July 20, 2006 this is regarding what he said ingame. 9x(sq) + 24x +16 (ax+B)(cx+d) is the answer. in this: a * c = 9 b * d = 16 (a * d) + (c * B) = 24 This means: a and c must multiply to equal 9. These choices are... 3,3 9,1 So: The answer is (3x_B)(3x_d) -or- (9x_B)(x_d) Now we know that b and d must multiply to equal 16. So b and d can be: 4,4 16,1 2,8 Now we have all choices of: (3x+4)(3x+4) (3x+16)(3x+1) (3x+2)(3x+8) (9x+4)(x+4) (9x+16)(x+1) (9x+2)(x+8) (9x+1)(x+16) (9x+8)(x+2) From this we can conclude: (3x+4)(3x+4) = 9x(sq) + 24x + 16 QED ok from the problem b4, ths is waht i though you had to do. this is what i thought you had to do. Example 9x(sq) + 24x + 16 step 1. Find the two numbers that you can multiply to get 16 (4,4) (2,8) (16,1) to name a few step 2. Do 9 times 4, plus 4. Or 9 times 2 plus 8, and reversed and etc. ( do you get what im saying) Until you got to 24. so this isnt right? That's almost right, which doesn't work in mathematics :( When there's no coefficient in front of the x^2 term - such as in x^2 + 4x + 4 - that works fine. But when there IS a coefficient in front of the x^2 term, such as in 2x^2 + x - 6, you need to take that into account. So what factors could lead to you getting a 2x^2 term?! The only way to get x^2 is by multiplying an x term and an x term! So you know that it will need to start out with (2x + __ ) (x + __), because then when you multiply out this 2x and x, you will get 2x^2. Everybody hug and spread the love :D Link to comment Share on other sites More sharing options...
Foooman Posted July 20, 2006 Share Posted July 20, 2006 (3x+4)(3x+4)----------{(3*4)+(3*4)}--------24 (3x+16)(3x+1) ---------{(3*1)+(3*16)}--------51 (3x+2)(3x+8) -------{(3*8)+(3*2)}------30 (9x+4)(x+4) ---------{(9*4)+(1*4)} ------40 (9x+16)(x+1) ------ {(9*1)+(1*16)} ------25 (9x+2)(x+8) -------- {(9*8)+(1*2)} --------74 (9x+1)(x+16) ------- {(9*16)+(1*1)} -----145 (9x+8)(x+2) ------- {(9*2)+(1*8)} --------26 These are all posible solutions. and yes you do the same thing to conclude the final answer after this step... Since (3x+4)(3x+4) has a middle term of 24..it is the correct one. Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 20, 2006 Author Share Posted July 20, 2006 (3x+4)(3x+4)----------{(3*4)+(3*4)}--------24 (3x+16)(3x+1) ---------{(3*1)+(3*16)}--------51 (3x+2)(3x+8) -------{(3*8)+(3*2)}------30 (9x+4)(x+4) ---------{(9*4)+(1*4)} ------40 (9x+16)(x+1) ------ {(9*1)+(1*16)} ------25 (9x+2)(x+8) -------- {(9*8)+(1*2)} --------74 (9x+1)(x+16) ------- {(9*16)+(1*1)} -----145 (9x+8)(x+2) ------- {(9*2)+(1*8)} --------26 These are all posible solutions. and yes you do the same thing to conclude the final answer after this step... Since (3x+4)(3x+4) has a middle term of 24..it is the correct one. just one question more, where did the (3X+16)(3X+1) and so on, come from, i know where the 9X came from but where the 3x? EDIT. NVM I FOUND OUT WHERE THE 3 CAME FROM Going To Sleep Now, thanks everyone and keep posting cause this stuff aint getting easier lol :shame: :lol: Click here to see my blog. Link to comment Share on other sites More sharing options...
Foooman Posted July 20, 2006 Share Posted July 20, 2006 In all of this I would take from it: In. Ax(sq) + Bx + C (ax+B)(cx+d) is the answer. in this: a * c = A b * d = C (a * d) + (c * B) = B EDIT: going to sleep. Link to comment Share on other sites More sharing options...
Bloodyrb Posted July 20, 2006 Share Posted July 20, 2006 Here is an example of a problem Factor the Trinomial X[squared] + 6X+9. (X + 3)squared Clue - quote me and you'll see the tiny text... EDIT: Here we go... huh (2x X 6) (2x X 6) = 4xÃÆââ¬Å¡Ãâò + 12x + 12x + 36 = ---------------------------- 4xÃÆââ¬Å¡Ãâò + 24x + 36 right? Link to comment Share on other sites More sharing options...
greenslime89 Posted July 20, 2006 Share Posted July 20, 2006 Here is an example of a problem Factor the Trinomial X[squared] + 6X+9. (X + 3)squared Clue - quote me and you'll see the tiny text... EDIT: Here we go... huh (2x X 6) (2x X 6) = 4xÃÆââ¬Å¡Ãâò + 12x + 12x + 36 = ---------------------------- 4xÃÆââ¬Å¡Ãâò + 24x + 36 right? Yes but in an exam you would lose a mark for that, you should take out a common factor, in this case 4, this would give you 4(X^2 + 6X + 9) Photos! Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 20, 2006 Author Share Posted July 20, 2006 ok thanks guy im back and i get most of this stuff now, but i still got some i need help with. ill try to finish what i can get to and then ill ask a few more questions Click here to see my blog. Link to comment Share on other sites More sharing options...
greenslime89 Posted July 20, 2006 Share Posted July 20, 2006 Pythagorus theorum rocks - I was raking through some old school papers and I found this test paper I did in first year (aged 12 Scotland system is different to most others) yes my writing was messy - SUE ME :twisted: Photos! Link to comment Share on other sites More sharing options...
SanFranciscoGiants Posted July 20, 2006 Share Posted July 20, 2006 :shock: :roll: Wow ive never heard of trinomials and I cant understand anything ur writing :lol: Link to comment Share on other sites More sharing options...
mad4u689 Posted July 21, 2006 Share Posted July 21, 2006 Pythagorus theorum rocks - I was raking through some old school papers and I found this test paper I did in first year (aged 12 Scotland system is different to most others) yes my writing was messy - SUE ME :twisted: Hehhee, I saw a t-shirt like that on cafepress :D Everybody hug and spread the love :D Link to comment Share on other sites More sharing options...
LP Posted July 21, 2006 Share Posted July 21, 2006 :( :cry: Link to comment Share on other sites More sharing options...
Quasar889 Posted July 21, 2006 Share Posted July 21, 2006 You guys think these trinomials are nasty, wait till you get to AP stat :shock: They have me doing quartic regressions and 2 Sample T-Tests! ZOMG! I <3 math though, so it isn't as bad as it sounds. (Specially with a TI-84 :3> ) I love that calc. You act like the game community is like the stinking bowels of hell.... In all reality.. its much.. much... worse. Link to comment Share on other sites More sharing options...
Foooman Posted July 21, 2006 Share Posted July 21, 2006 You guys think these trinomials are nasty, wait till you get to AP stat :shock: They have me doing quartic regressions and 2 Sample T-Tests! ZOMG! I <3 math though, so it isn't as bad as it sounds. (Specially with a TI-84 :3> ) I love that calc. Just got my AP Stat test score from last year. 5 :mrgreen: Stat is easy; it's English, with some harmless math. Link to comment Share on other sites More sharing options...
weezcake Posted July 21, 2006 Share Posted July 21, 2006 You guys think these trinomials are nasty, wait till you get to AP stat :shock: They have me doing quartic regressions and 2 Sample T-Tests! ZOMG! I <3 math though, so it isn't as bad as it sounds. (Specially with a TI-84 :3> ) I love that calc. Eh, personally, I believe that stat is equivalent to basic algebra. I don't understand why people think it's so hard! (I did have trouble in calculus though, hehe) Stats = get formula/procedure, plug in number, get answer. :mrgreen: ==================================Retired tip.it moderator.Teaching and inspiring. Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 21, 2006 Author Share Posted July 21, 2006 ok now theres a differnt problem, it says 9X[squared]81. Is this one difficult? Click here to see my blog. Link to comment Share on other sites More sharing options...
Foooman Posted July 21, 2006 Share Posted July 21, 2006 (3x+9)(3x-9) Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 21, 2006 Author Share Posted July 21, 2006 x^3+11x^2+28x Click here to see my blog. Link to comment Share on other sites More sharing options...
Foooman Posted July 21, 2006 Share Posted July 21, 2006 x(cubed)+11x(sq)-28x note that the last term has an x. This means that one of the factors is going to have 2 x's. note that that the first term is cubed. This means that one of the factors is gonig to have an x(sq). note that the both signs are positive. This manes that both factors will have positive signs. Now we need the factors of 28 that add up to 11. These happen to be 7 and 4. (x(sq)+4x)(x+7) (x(sq)+7x)(x+4) Are both correct answers. Link to comment Share on other sites More sharing options...
quakingmoose Posted July 22, 2006 Share Posted July 22, 2006 EDIT - There is the basics on Factoring, if you wanna know how to reverse.. you simply multiply the ( )'s together, then you group all like terms and booya! theres Standard form. With Trinomials, theres: Standard form - y=ax(squared) + bx + c X-Intercept form - y=(x+a)(x+B) , a & b = any number You can switch back and forth between through several methods. If you would like to go from Standard to X-Intercept (this is hard, Ill try to explain) you need to do this: Example 1) a = 1 , b = 1 , c = -6 So the equation is - y=x(squared) + x - 6 >>>Are you with me? To get the leading term of x(squared), each first term is x, therefore: y = (x )(x ) Then we need to find what else are in the ( ). The product of the last terms must be -6. Possible answers are: + 6 and - 1 - 6 and +1 + 3 and - 2 - 3 and +2 This tells us that our possible answers to this problem will be: (x+6)(x-1) (x-6)(x+1) (x+3)(x-2) (x-3)(x+2) Then you need to test, to see which one is the RIGHT answear, each of these pairs to see which will yield the correct middle term when they are added together. (x + 6)(x - 1) gives middle term 5x. (x - 6)(x + 1) gives middle term -5x. (x + 3)(x - 2) gives middle term +x. YEA!!!!! (x - 3)(x + 2) gives middle term -x. Therefore the answear is y = (x + 3)(x - 2), in X-intercept form. THIS WHOLE PROCESS IS CALLED FACTORING! My brain hurts now. 3 Solo Hilts (2 Saradomin, 1 Bandos)10 Solo Saradomin Swords48 Abyssal Whips217 Barrows Items Link to comment Share on other sites More sharing options...
nightshade53 Posted July 23, 2006 Share Posted July 23, 2006 I swear they (expressions of order 2) are called Binomials..as in the binomial expansion :roll: , then cubics (order 3) and quartics (order 4).. to solve to general binomial you do this: A(x^2)+B(x)+C = 0 <-- Set it equal to 0 then use the formula: x = (-(B^2) ÃÆââ¬Å¡Ãâñ ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡((B^2)-(4*A*C)))/2*A :XD: Link to comment Share on other sites More sharing options...
Aznhuskarl Posted July 24, 2006 Share Posted July 24, 2006 x = (-(B^2) ÃÆââ¬Å¡Ãâñ ÃÆâÃâ¹Ã¢â¬Â Ãâ¦Ã¡((B^2)-(4*A*C)))/2*A ah...that formula...a lot fo ppl from my high school SINGS that formula with that Carmen Campagne's song. I used to be able to do all those binomals and trinomals without writting any calculation. Ahh...high school math. That was pretty easy. -=Aznhuskarl=- Cleric-=20Cent=- JuggernaughtMore to come... Link to comment Share on other sites More sharing options...
lifeguard200 Posted July 24, 2006 Author Share Posted July 24, 2006 y=2x+7 over 14 i put it like problem wise and it looks wierd so i had to type it this way Click here to see my blog. Link to comment Share on other sites More sharing options...
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