Space

[Earth]

Good, you're thinking like a tavernite again.

[archimage_a]

First, I said the wire was ideal so resistance was ignored. I didn't say 'It is a super conductor' I said resistance is ignored... I was trying to bypass a string of calculations which would result in a net loss of a few joules and be completely inconsequential in the grand scheme of things.

You then seized on this and demanded infinate power. I, in my naivety, assumed you knew what you were talking about and agreed to a system which was scientifically incorrect...I knew it was Scientifically incorrect, but, given that this is a game, was willing to ignore that so you could have your weapon.

 

Secondly, Mather, your 'weapon' would work far better if you had a 13,000,000W power source, rather than dance around trying to turn 100 Watts into 13,000,000 Watts...Since energy cannot be created or destroyed, thus Watts have to stay the same unless new power is added...And transformers, of which Tesla Coils are a subcatagory, do not add power, they simply convert Amps into Volts and Visa Versa.

The number of Watts in the system stays proportionally the same.

 

Thirdly:

The world's largest currently existing 2-coil Tesla coil is a 130,000-watt unit.

A large Tesla coil of more modern design often operates at very high peak power levels, up to many megawatts.

http://en.wikipedia.org/wiki/Tesla_coil

Tesla Coils work in Watts, not Volts.

 

 

Work must be done by an external influence to "move" charge between the conductors in a capacitor. When the external influence is removed the charge separation persists in the electric field and energy is stored to be released when the charge is allowed to return to its equilibrium position. The work done in establishing the electric field, and hence the amount of energy stored, is given by:

http://en.wikipedia.org/wiki/Capacitor#Energy_storage

Capacitors work in Watts, not Volts.

 

Forthly:

0,0125*(5cm diameter * 5 turns + 5cm extra)/5mm² = 0,00075Ohm

Rho: Resistivity of Copper is 0.0000000205 Ohms per meter.

Length: 5 CM diameter, so the circumferance is 15.7 Centimeters, times 5(number of turns) is 78.54 Centimeters, plus 5 is 83.54 Centimeters, or 0.8354 meters.

Cross section: 5 mm diameter, 2.5 mm radius, or 0.0025 Meters. Is 0.0000196 Square meters.

So:

0.0000000205* (0.8354/0.0000196)

Or Rho*42,622.5

0.00087376125 Ohms.

 

100/0,00075=133,333.333A

Ohm's Law states that Watts=I^2*R

So rearranged, I^2=W/R

Therefore: 100/0.00087 is 114942.52873563218390804597701149, and that square rooted is 339.03175181040519159411916326503 Amps.

 

Ohm's Law(same link) also states that W=V^2/R

So, rearranged, V^2=W*R

Therefore: 100*0.00087 is 0.087, square rooted is 0.29495762407505251668688367204057 Volts.

 

We then check this:

0.29495762407505251668688367204057*339.03175181040519159411916326503= 99.999999999999999999999999999798 (Given I have rounded up the resistance this can be taken as 100.)

 

 

So, after a lot of fiddling about with theories which were wrong, we have now reconciled Ohm's Law, Capacitors, Watts and Volts.

 

1/133,333.333~0,0000075second discharge time

F=s/R

Rearranged to s=F*R

If the capactior has a capacitance of 10 MicroFarads, and discharges at it's max, then F=0.00001 Farads.

R= 0.00087 Ohms

Therefore 0.00001*0.00087 = 0.0000000087 Seconds.

 

Which eliminates yet another unknown in the system.

 

We can then check this using the equation F=(A*s)/V

A*s=339*0.0000000087 = 0.0000034713

(A*s)/V = 0.0000034713/0.3 = 0.000011571 (Which, again, given I am rounding, can be taken as 0.00001)

 

We can then double check using the equation F=(W*s)/V^2 Or F=J/V^2

W*s=100*0.0000000087 = 0.00000087 (Joules)

V^2 = 0.09

(W*s)/V^2 = 0.00000087/0.09 =0.00000966666666667 (Which again, due to rounding, can be taken as 0.00001)

 

So we know now that, at the moment of discharge(And you can use these figures to check as they are unrounded):

Watts = 100

Volts= 0.29495762407505251668688367204057

Amps = 339.03175181040519159411916326503

Seconds = 0.0000000087

Resistance = 0.00087376125

Copper Rho = 0.0000000205

Farads= 0.00001

 

 

 

 

 

 

 

 

 

 

 

Anywho, now that it has been proved, beyond a shadow of a doubt, given that no laws of physics are broken and everything works with everything else, I can safely say, without a shadow of a doubt, that you are wrong Mather.

The laws of Physics say you are wrong.

The laws of Thermodynamics say you are wrong.

The laws of Mathematics say you are wrong.

People alive 200 years ago say you are wrong.

People alive 100 years ago say you are wrong.

People alive last year say you are wrong.

People alive today say you are wrong.

I say you are wrong.

Wikipedia says you are wrong.

Wyvern and Retech say you are wrong.

 

So you will excuse me for not being terribly bothered that you and 3 of your friends say I am wrong...

 

Especially when all four of you failed to notice that the equation for Rho and Resistance is not:

(

transcribed as:

Rho = Voltage * Current.

And

Resistance = (Rho*Length)/Area

)

When even the most cursory of glances at Wikipedia would show that:

Resistance is equal to Rho * (Length/Area)

 

And Rho is:

(Volts/Meter)/(Amps/Meter Squared)

 

Especially when all four of you believe that you can create electricity by running electricity through a copper wire.

Especially when all four of you believe that 1/Ampage equals discharge time.

Especially when you get the Resitivity of Copper wrong.

 

 

 

Using Hard Science doesn't mean you can use a mixture of soft and hard science...It means you have to use Hard Science at every level.

So now that we have resolve the fact that you know less than I do about Electrical Science...Please...Stop embaressing yourself and your friends...

 

 

 

Nex, Ross, would you mind locking the thread for the duration that my computer is being fixed, removing any posts after this one so I don't have to face Mather being angry that his version of Science doesn't marry up with reality.

[Retech]

Note that I don't know anything about electrics, but was just pointing out the mathematical inaccuracies.

 

That's what I do. :shades:

[Nexaduro]

*Ahem*

 

Technically I said any further posts on the subject would be deleted... But I suppose that's an acceptable closing statement... But seriously, anything else is going in the bin.

[Seraphi]

Righto. Locked on request. Just shout when you would like it unlocked again

[Nexaduro]

I thought we weren't supposed to lock on request?

[Seraphi]

If it's going to prevent this argument from continuing, then I think it's okay.

 

Tempers were rising, and even with mature people it can very quickly turn into a flame war.

[Nexaduro]

Is your computer fixed yet, Archi?

[archimage_a]

No. I will post tell Ross/You when it is...

[Nexaduro]

Alright. I was just too bored to avoid poking. :D