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Mathmatics is basically following a set of rules to a desired outcome...hence why computers can do it far better than humans. The only area Humans excel over computers is deciding which set of rules to use.

Errr Graphs are considerably easier...

Nepotism.... Anywho, Spork is asking, not Stork. :rolleyes: And no worries Mather :grin:

No Icouwange, its just your Boss. :grin:

The term you are looking for is 'Profitable' :thumbup:

Game didn't have ATMs :rolleyes: Also, I knew GPA was Grade Point Average...We still don't have it in Britian.

I am not sure which RTC game I had, I remember I kept intentionally designing the rollercoaster that went up and down the same bit of track, too short. It was a pain, since you had to make small changes every time the cart went off the rails otherwise people were too scared to go back on it. Also remember when I built a park which went: Ride, walled off area with food, drink and toilets, ride, walled off area with food, drink and toilets...and just carried on with that kind of a park, ended up netting so much money, since you couldn't leave without going through the rides (Mwhahahahaha!)...though people sometimes ran out of money half way round, so I needed lots of cleaners and security. Also, in later games I began getting more Dungeon Masterish, so had a Ride Maze, so you could choose to go on one of four rides(less in the corners and edges) which would advance you through the maze....Unsuprisingly they did not respond well to my meta-ride, since there was no logical pattern to it (I was 10-14, I still though the computer was capable of thought...though most people seem to think that computers can do that so its not neccessarily a young thing), so most people got to an area with no money or no rides they liked =( Also remember in one game of Themepark World I designed the most awesome themepark ever, and sold it for 13.4 billion Dollars...In a game where the best rides cost $40,000... But then I screwed up, brought an area in the antarctic, thinking of building a snow park, but it was exactly the same as everywhere else... <_< So got 5 people a year, despite having spent 2 million on rides, and had hundreds of staff patrolling the park.

Falador Tavern: We are gonna stalk you if you are smart. :shame:

Way ahead of you =P [hide][/hide] Each province would have 5 villages and such. And yes, thats a good point, the game was realtime so I guess we should take it up to 50 per village/monastry/whatever per day.

Idea for a Hegemony that could be modded by anyone without much problem: 1,000 AD time period. Large Province based system, for instance Britian is split into Wales, South East, Cornwall, Mercia, York and the Highlands. Ireland as North and South Ireland. Each province contains villages, monesteries, farms and costal Villages, and one Town. Villages generate money, Monestries generate Piety, Farms generate food...and Coastal Villages generate Money and Food. By default 1 of each. Money is money. Piety is used for special actions. Food is the max number of units you can support, and generates tax. Towns contain buildings. There are three types of building: Civil= Buildings that increase the amount of Food/Money/Piety, extra tax, and affect rebellion chances. Training= Buildings that let you train specific units. Defence= Buildings that defend the town. Units are divided into 3 classes: National Units= Units that can be built anywhere in your empire. You only have 1 of these and decide at the beginning of the game. Local Units= Units that are built in the province, regardless of who controls it. Siege Units= Catapults and whatnot. All units above Peasents require certain buildings...Bow Wielders need Fletchers, Sword Wielders need Swords...ect. More heavily armoured units need various armourers. If your province builds swordsmen, peasents, bowmen and light calvery, then building advanced armouries is useless. Armies are controlled by Generals. Generals can be levelled up. Armies can cross anyone's land. Armies can plunder villages and conquer towns. Each plunder takes 1 Year and generates about 700 Gold (More if your General is skilled at looting) Spies can be hired and sent to another country. There is then a chance that the spy will be hired as a General. If they are hired as a General then you can have the General revolt with all of their troops and join your side. Spies can also be used to assassinate leaders of other countries, leading to increase discontent and resets all treaties and what not. Rebellions crops up when rebel feeling gets too high: AKA when you tax people too much, commit dishonourable acts(breaking treaties), after you conquer someone. Rebels act like enemy armies, but once they capture a town will become an independant nation. Special actions. They cost 1,000 Piety and Piety is capped at 1,000. You can promote troops, increase General Skill, decrease Rebellious feelings, kill a foreign leader, force them into a non-aggression pact (Doesn't stop them, but makes it dishonourable to attack you). Players would be responsible for everything in their empire and would just need to PM stealth actions to the Mod and post public actions. Mod would be responsible for keeping the offical map, resolving battles and random events-Rebellions, Mercenaries, King Deaths and NPC wars.

We don't have GPA...(I assume America just has a unified GPA system...Kinda confusing if they don't) We do have a UCAS Tarriff, but its not really the same as GPA, so far as I can see. You get an overall grade for your course and that translates as a number of points: http://www.ucas.com/students/ucas_tariff/tarifftables/

It was, when I was applying, £750 was means tested, and everything else was 'everyone is entitled'

Nah, it is gonna be unchanged, since they still give out loans to anyone who applies...Just means the Government is gonna have to pay out more money in the short term, though, since the money goes back to the government it just screw the people who actually pay for it themselves. Which, to my mind, just inspires not working. However, you can now earn £19,999.99 without having to pay back the money...which is good. Laptop update: Got it back, installed Vista from a recovery disk...unfortunately it was the recovery disk for this computer, not the laptop, so the laptop doesn't have wireless, and the network adapter doesn't seem to connect to the interweb when I plug in the cable. So have ordered the new disk for £33. However, the repair price for the laptop decreased from £260 to £75...Which was very impressive.

Britian has: Primary(Elementary) education that is compulsory. Secondary Education that is also compulsory. A wierd gap between Secondary Education and higher Education...where you get EMA, 30 pounds a week, if you are below the means test threshold, and in education. Then Higher Education costs money, but the Government has a Student Loan company that gives out interest-free loans to students, for their studies. And after 25 years any remaining debt is written off. Two loans: 1 covers tuition. 1 covers living costs. System works, though it is convoluted...like most things British.

Ok, you will be pleased to know that the laptop is coming back tommrow, new hard drive and all that jazz. Doesn't have windows installed on it <_< and I don't have a vista disk <_< <_< . However, I still have the product code and a backup disk(Which appears to be the right size). Ergo, if the back up disk doesn't work, which is probable, then I can either, get my hands on a Vista Disk and use my product code, and all should be well...or I can call up Microsoft and have them send a replacement disk out...supposedly for free, more likely for a fee, ideally less than the cost of buying the disk itself =P

First, I said the wire was ideal so resistance was ignored. I didn't say 'It is a super conductor' I said resistance is ignored... I was trying to bypass a string of calculations which would result in a net loss of a few joules and be completely inconsequential in the grand scheme of things. You then seized on this and demanded infinate power. I, in my naivety, assumed you knew what you were talking about and agreed to a system which was scientifically incorrect...I knew it was Scientifically incorrect, but, given that this is a game, was willing to ignore that so you could have your weapon. Secondly, Mather, your 'weapon' would work far better if you had a 13,000,000W power source, rather than dance around trying to turn 100 Watts into 13,000,000 Watts...Since energy cannot be created or destroyed, thus Watts have to stay the same unless new power is added...And transformers, of which Tesla Coils are a subcatagory, do not add power, they simply convert Amps into Volts and Visa Versa. The number of Watts in the system stays proportionally the same. Thirdly: http://en.wikipedia.org/wiki/Tesla_coil Tesla Coils work in Watts, not Volts. http://en.wikipedia.org/wiki/Capacitor#Energy_storage Capacitors work in Watts, not Volts. Forthly: Rho: Resistivity of Copper is 0.0000000205 Ohms per meter. Length: 5 CM diameter, so the circumferance is 15.7 Centimeters, times 5(number of turns) is 78.54 Centimeters, plus 5 is 83.54 Centimeters, or 0.8354 meters. Cross section: 5 mm diameter, 2.5 mm radius, or 0.0025 Meters. Is 0.0000196 Square meters. So: 0.0000000205* (0.8354/0.0000196) Or Rho*42,622.5 0.00087376125 Ohms. Ohm's Law states that Watts=I^2*R So rearranged, I^2=W/R Therefore: 100/0.00087 is 114942.52873563218390804597701149, and that square rooted is 339.03175181040519159411916326503 Amps. Ohm's Law(same link) also states that W=V^2/R So, rearranged, V^2=W*R Therefore: 100*0.00087 is 0.087, square rooted is 0.29495762407505251668688367204057 Volts. We then check this: 0.29495762407505251668688367204057*339.03175181040519159411916326503= 99.999999999999999999999999999798 (Given I have rounded up the resistance this can be taken as 100.) So, after a lot of fiddling about with theories which were wrong, we have now reconciled Ohm's Law, Capacitors, Watts and Volts. F=s/R Rearranged to s=F*R If the capactior has a capacitance of 10 MicroFarads, and discharges at it's max, then F=0.00001 Farads. R= 0.00087 Ohms Therefore 0.00001*0.00087 = 0.0000000087 Seconds. Which eliminates yet another unknown in the system. We can then check this using the equation F=(A*s)/V A*s=339*0.0000000087 = 0.0000034713 (A*s)/V = 0.0000034713/0.3 = 0.000011571 (Which, again, given I am rounding, can be taken as 0.00001) We can then double check using the equation F=(W*s)/V^2 Or F=J/V^2 W*s=100*0.0000000087 = 0.00000087 (Joules) V^2 = 0.09 (W*s)/V^2 = 0.00000087/0.09 =0.00000966666666667 (Which again, due to rounding, can be taken as 0.00001) So we know now that, at the moment of discharge(And you can use these figures to check as they are unrounded): Watts = 100 Volts= 0.29495762407505251668688367204057 Amps = 339.03175181040519159411916326503 Seconds = 0.0000000087 Resistance = 0.00087376125 Copper Rho = 0.0000000205 Farads= 0.00001 Anywho, now that it has been proved, beyond a shadow of a doubt, given that no laws of physics are broken and everything works with everything else, I can safely say, without a shadow of a doubt, that you are wrong Mather. The laws of Physics say you are wrong. The laws of Thermodynamics say you are wrong. The laws of Mathematics say you are wrong. People alive 200 years ago say you are wrong. People alive 100 years ago say you are wrong. People alive last year say you are wrong. People alive today say you are wrong. I say you are wrong. Wikipedia says you are wrong. Wyvern and Retech say you are wrong. So you will excuse me for not being terribly bothered that you and 3 of your friends say I am wrong... Especially when all four of you failed to notice that the equation for Rho and Resistance is not: ( transcribed as: Rho = Voltage * Current. And Resistance = (Rho*Length)/Area ) When even the most cursory of glances at Wikipedia would show that: Resistance is equal to Rho * (Length/Area) And Rho is: (Volts/Meter)/(Amps/Meter Squared) Especially when all four of you believe that you can create electricity by running electricity through a copper wire. Especially when all four of you believe that 1/Ampage equals discharge time. Especially when you get the Resitivity of Copper wrong. Using Hard Science doesn't mean you can use a mixture of soft and hard science...It means you have to use Hard Science at every level. So now that we have resolve the fact that you know less than I do about Electrical Science...Please...Stop embaressing yourself and your friends... Nex, Ross, would you mind locking the thread for the duration that my computer is being fixed, removing any posts after this one so I don't have to face Mather being angry that his version of Science doesn't marry up with reality.

Just establishing that I was right....again... If you opened up a route around the capacitor then the capacitor would be ignored, and the charge in the capacitor would decay. The Ampage would be the same, and the charge of the circuit would remain the same. Though I am guessing you mean some sort of a second circuit involving the Capacitor. So, to summerise your idea: You have a power source of some type, pumping energy into a capacitor. When the Capacitor reaches 100 Watts it switches to a seperate circuit. The new circuit is Earthed at either end, allowing energy stored in the Capacitor to be discharged(not sure which way the energy would go so feel free to include 'The capacitor is reversed'). Since Resistance is 0*, then by Ohm's Law, Ampage must be Infinate. Which means the number of Volts is 100/Infinate. Preserving the number of Watts in the circuit, meaning no new energy is created, thus inkeeping with the laws of thermodynamics. *Resistance is never actually 0, since there are always other forces acting on the materials, causing tiny degrees of resistance...So 0 Resistance only exists in simulator land, in the real world the resistance is soooooooooo tiny it has no effective bearing on things, though it does have a bearing, inkeeping with the laws of mathematics. This figure will be known as P^-1. Then energy is transfered into a transformer, which steps up the 0 voltage, and steps down the infinate ampage by a factor of 100, resulting in a net change of 0, thus inkeeping with the laws of mathematics and laws of thermodynamics.** **If this were a practical experiment then: The energy is transfered into a transformer, which steps up the P^-1 voltage, and steps down the P ampage by 100. Where P is near infinate ampage. Then we need to work out the resistance of this part of the thing: R= Rho*(Length of Conductor/crossection of wire) So cross section is 0.0000007853981 Square Meters The length would be at least 0.101 meters. Rho would be P^-1. So: 128,597P^-1 Ohms So I^2*R, which would be 100P^2*128,567P^-1 Which is 12,856,700P Joules of heat. Since the system itself only has 100 Watts in that means: A) The system doesn't work, the moment the number of Joules of Hear exceed the number of Watts the system collapses. B) The wire is gonna break down because electrons are getting ripped out to supply energy. C) Something else. Anyway, lets assume that doesn't happen this once. Then energy is transfered into a transformer, which steps up the 0 voltage, and steps down the infinate ampage by a factor of 3,200, resulting in a net change of 0, thus inkeeping with the laws of mathematics and laws of thermodynamics.*** ***If this were a practical experiment then: This energy is then transfered to a new transformer, which steps up the energy again, this time by a factor of 3,200. So the 100P^-1 voltage becomes 320,000P^-1, and the 100P Ampage becomes 320,000P. Then resistance, which would be: Cross section is 0.0000007853981 Square Meters The length would be at least 3.205 meters. Rho would be P^-1. R= 4,080,733P^-1 Ohms Then 320,000P^2 * 4,080,733P^-1 Which equals: 1,305,834,560,000P Joules. Again: A) The system doesn't work, the moment the number of Watts is exceeded, the current is stopped. B) The wire is gonna break down because electrons are getting ripped out to supply energy. C) Something else. Anyway, lets assume that doesn't happen...again. Once it has been stepped up to this height, a human then touches it(Since the whole method of transferance is get to be explained). The human has a resistance of 500,000 Ohms, on average.**** The current, being near infinate, generates excessive resistance. At rate of I^2*R...Or 320,000P^2*R*t Which is 102,400,000,000P*R*t Now, a human has a Rho of around 500,000 Ohms per meter. Lets say left arm, across the torso and down into the right foot. On me it is 97 Centimeters from my Left Hand to my heart and 130 Centimeters from my heart to my Right Foot. Which has a net of 227 Centimeters, or 2.27 meters. I will also work out if you hit directly next above my heart, so 1.3 meters.***** Cross section is between 7 centimeters on my forearm, and 40 cenimeters from hip to hip. If we take the average at about 20 Centimeters(Given my leg is around that across), 0.031 Square meters We get 500,000 * (2.27/0.031) 500,000*0.07037 = 35,185 Ohms. 102,400,000,000P*35,185*t 3,602,944,000,000,000P*t t should be P^-1, since it is the inverse of the ampage. So that takes it to 3,602,944,000,000,000 Joules of Heat. *****We get 500,000 * (1.3/0.031) 500,000*0.0403 = 20,150 Ohms. 102,400,000,000P*20,150*t 2,063,360,000,000,000P*t t should be P^-1, since it is the inverse of the ampage. So that takes it to 2,063,360,000,000,000 Joules of Heat. Which again: A) The system doesn't work, the moment the number of Watts is exceeded, the current is stopped. B) The skin is gonna break down because electrons are getting ripped out to supply energy. C) Something else. ****If we take it as theoretical then: The current, being infinate, generates infinate resistance. At rate of I^2*R...Infinate^2*R*t Infinaty squared is infinaty, multiplied by 20,150 Ohms (or 35,185 Ohms, makes no difference) is infinaty, times by 0, is 0. So the number of Joules of heat is also 0. Which is not really sufficent for anything. So, to summerise: Theoretically, zero time passes once the capacitor has fired, meaning that no energy can actually be transfered. Practically, even in the most perfect situation, there will be a tiny amount of resistance(P^-1), and this tiny amount of resistance, together with the giganormous amount of Current, leads to Ohmic Heating which would destroy anything it touches...including the circuit...Or expend the 100 Watts of energy and become useless. Disclaimer: This is based, as far as inkeeping with the laws of physics and what Mather said, as I can manage. I don't know that if you Earth a capacitor at both ends that it will discharge using Ohm's Law, and Rho subsituting R. I imagine it wouldn't. I imagine that nothing would happen, and you would have to send a charge through the capacitor to make it discharge, and that this charge would carry the surge of volts around the circuit, probably blowing something up. Anyway, I think that is everything, I have made my final decision to completely disallow the weapon...since it doesn't seem to work, on any level. If you have a problem, then feel free to post that you have a problem, however I consider the matter closed... I am also using this as a precedent to disallow hard science arguements in the future, as this has wasted over 12 hours of my time and lead to me being accused of Raping the laws of Physics to suit my own ends...Despite me approaching this a calm and analytic fashion, explaining, at every stage, the thought process, at great length, using the actual numbers, rather than abbreviations which can be misleading and inaccurate if there is a typo...In short I have done everything physically possible to do this as objectively as possible...and still it has lead to me being accused of biased, that just hurts.

http://en.wikipedia.org/wiki/Capacitor#Current-voltage_relation The current stays the same either side of the capacitor. The Capacitor only stores voltage. Ergo the 'new' Ampage doesn't need to be calculated, since it is still known. Its really quite obvious, since current has to flow around the entire circuit otherwise the voltage wouldn't flow.

You didn't prove it possible. You didn't show why the limit was off. I said an ideal material, ignoring the resistive losses. Wattage was always more important, Ohms have never been important in working out Volts or Current.

In your simulation: Voltage and Amps go into capacitor...Then the Amps are magicked away...Care to explain how this is accomplished? Sure, you don't care about the amps, but they must 'go' somewhere?

Mather, get your teacher to explain what a Watt is. I have zero interest in the resistance of the wire because it is entirely inconsequential. The only thing that actually matters is the number of watts you start with. Make special referance to the Voltage*Current = Watts part of conversation. Oh, and respond to my posts otherwise I will stop reading yours....I do not appreciate specifying how your system doesn't work, to have you then restate your system without invalidating any of the flaws I specified.

STEPPING UP HAS NOTHING TO DO WITH RESISTANCE! http://en.wikipedia.org/wiki/Transformer#Ideal_power_equation AHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH *Scores with the words 'If the voltage is increased, then the current is decreased by the same factor.' into Mather's Forehead*

Sigh. You need a core: The use of a magnetic core can enormously concentrate the strength and increase the effect of magnetic fields produced by electric currents and permanent magnets. http://en.wikipedia.org/wiki/Magnetic_core Also you show a basic misunderstanding of how electricity works, I will now show you how your system doesn't work: Imagine you have a 2 volt battery. You connect this battery to an inverter, making it AC. You then attach a silver cable to the inverter. I=V/R So 2/0.000000016 = 125,000,000 Amps. We then step this up, through 1 to 125,000,000 (Or some multiple of that) turns. Generating 1 Amp and 250,000,000 Volts. We then check the Wattage, it is 250,000,000. Then we attach another siver cable to it, which resets the Amps to Unknown...Somehow. I=V/R So 250,000,000/0.000000016 = 15,625,000,000,000,000 Amps. We then step this up, through a 1 to 15,625,000,000,000,000 turn transformer (or some multiple). Generating 1 Amp and 3,906,250,000,000,000,000,000,000 Volts. We then check the Wattage, it is 3,906,250,000,000,000,000,000,000. Now...Since perpetual motion and perpetual energy are still considered to be unrealistic...we can safely assume that this is not how electricity works. So how do we define the number of Amps we start with? Well, the obvious solution is the number of Watts in the system, divided by the number of Volts, which is a rearrangement of V*I=W. So if there are 100 Watts to start with, and 100 Volts, the system, therefore, has 1 Amp. So lets see how this fares in the INFINATE ENERGY MACHINE! Imagine you have a 2 Volt, 2 Watt Battery. You connect this battery to an inverter, making it AC. You then attach a silver cable to the inverter. I=W/V I=1 We then step this up, through 1 to 125,000,000 (Or some multiple of that) turns. Generating 0.000000008 Amps and 250,000,000 Volts. Then we attach another silver cable to it. The number of Amps are already known, no need to figure it out again. Lets check the number of watts... V*I=W W=2 We then step this up, through a 1 to 15,625,000,000,000,000 turn transformer (or some multiple). Generating 0.000000000000000000000000512 Amps and 3,906,250,000,000,000,000,000,000 Volts. Lets check the Wattage: Thats amazing, its 2...Still. So we have: Ohmic-Infinate Power Generator on the one hand...not supported by any experimental evidence. Or, on the other hand, we have Watt-Finate Power Generator...Which is supported by all experimental evidence so far... So, clearly, you have misunderstood how current works.

I thought it sounded Sarky =P. And its like the whole 'Guns don't kill people, People kill people.' A game doesn't suck your entirely life in unless you feed your life into it.

What on earth are you talking about Mather? I never talked about resistance of the wire. If you have a 1 centimeter wide core, then the length of the wire would be Pi*Radius^2*number of turns...Which is 3.124*0.5^2 = 0.785 0.785*16,005 = 12,570.3 Centimeters Ergo, the length of the wire would be 125 meters. (Ignoring the angular cost, since it does not all stay on the same latitude.) Assuming 25 centimeters is like assuming that the reason someone's leg hurts is because a shark bit it off...Great if they lived by a shark infested lake, were missing a leg and were screaming 'A shark took it!'...not so great if their leg is alright except for a small round burn mark and they are saying 'It fell out of the dashboard charger slot...what are you doing with that saw!?' I also said ideal wire, as in wire with 0 resistance...Hence I ignored resistance throughout the entire endevour, or at least until it entered the human. Anyway, you are incorrectly applying Ohms Law...As we could equally apply it to the Human: I=V/R V=32,000,000 R=2,500,000 =12.8 Amps...which is obviously not 0.00714 Amps, as you stated. The resistance, in fact, would have to be considerably higher for the number of amps you stated to occur. And no, that does not 'prove' it is fatal, because, according to your calculations: http://en.wikipedia.org/wiki/Watt#Definition We start with: 100 Volts and 228,570 Amps...Which equates to 22,857,000 Watts. And we end with: 32,000,000 Volts and 0.00714 Amps...Which equates to 228,480 Watts. If we took 12.8 Amps as the final figure: 32,000,000 Volts and 12.8 Amps...Which equates to 409,600,000 Watts. Of which, none match. Comparatively: I start with 100 volts and 1 Amp...Which equates to 100 Watts. And end I have 32,000,000 Volts and 0.000003125...Which equates to 100 Watts. Ergo, using Ohm's law irresponsibly is irresponsible. *Strings up the 'Archi was right' Banner* (Over the years it has really paid for itself) Now, given that I spent around 3 hours on this, and you seem to have spent 3 minutes on this...Can you see why 'hard science' isn't good for the moderator? It essentially requires the moderator to completely ignore the player's calculation, using only their starting point as referance, and then explore all the various factors...Post...Wait for the player to post 'While I conceed that the number should be lower, I still believe that you have made a mistake, and therefore I am still right', which is usually wrong, thus requiring the mod to do another calculation, this time showing how the player interpretation is wrong: You started with 80 mAmps. I proved that was wrong, and it was 3.1 MicroAmps. You posted that it was 7 mAmps. I proved that was wrong, and restated it was 3.1 MicroAmps. To consider: The lethality of an electric shock is dependent on several variables: 1) Current (the higher the current, the more likely it is lethal) 2) Duration (the longer the duration, the more likely it is lethal - safety switches limit time of current flow) 3) Pathway (if current flows through the heart muscle, it is more likely to be lethal) 4) Voltage Presently, you have ultra-low current, ultra-low duration, no defined pathway...and a boatload of voltage.