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Equal to 1?

Featured Replies

So, if 3 = 1, then 3 = 3/3...

 

 

 

Hmmm :-k

 

 

 

 

 

 

 

(3 = 1 btw, google it :))

I'm Jake Milroy

 

(3 = 1 btw, google it :))

 

 

 

Yeah.. telling us to google something when we don't have something exact to look for doesn't help us at all.

Brahh, I'll hunt up some textbooks tomorrow. For now, it is bed time. And, btw, Devilsdragon, I wasn't forcing you to google anything.

 

 

 

 

 

 

 

EDIT

 

 

 

Let j and any power or coefficient of j, eg 2j, be a complex number, and not real. To solve this equation, we gather all the imaginary parts and all the real parts and compare. If you hate maths, look away now:

 

 

 

(1 + j)z = 3 + j

 

z + zj = 3 + j

 

 

 

z = 3 (that's the comparison of the real bits)

 

zj = j (and that's the imaginaries)

 

 

 

:. 3j = j

 

:. 3 = 1.

 

 

 

 

 

 

 

There's an abridged version. It's sort of hard to teach, I'm glad I'm not a teacher. :)

I'm Jake Milroy

Brahh, I'll hunt up some textbooks tomorrow. For now, it is bed time. And, btw, Devilsdragon, I wasn't forcing you to google anything.

 

 

 

I ment that when I went to google it, I couldn't find it. And I never used the word force, I said tell, which is what you did.

Ok..wth. Thats pretty crazy. #-o :| :wall:

signaturecj5.jpg

Also, if you think about it, what would you add to .9 repeated to get 1? It would have to be .0 repeated but where would you add the 1 inside of the .0 repeated?

 

(1 + j)z = 3 + j

 

z + zj = 3 + j

 

z = 3 (that's the comparison of the real bits)

 

zj = j (and that's the imaginaries)

 

:. 3j = j

 

:. 3 = 1.

 

 

 

 

That̢̢̮ââ¬Å¡Ã¬Ã¢ââ¬Å¾Ã¢s some horrible maths and ignores many fundamental properties of complex numbers.

Nope, you're dividing by 0.

 

 

 

(1+j) z = 3+ j

 

Z + jz = 3 + j

 

 

 

Z- 3 = j - jz

 

 

 

1 = (j - jz) / (z-3)

 

 

 

Therefore if Z = 3, it's undefined. Which is why you're getting 3=1.

 

 

 

1 = [(z-1 ) j ] / (3- z)

 

 

 

As (z- 1) * j must equal a real number, since Z is a real number and the value is 1, there's no solution as j is imaginary.

 

 

 

Pwned.

Never thought of that before.

 

I'll join Biabf. GAH?!

 

 

 

I'll join both of you.. GAH?! I mean it's summer... I'm not supposed to think =;

 

 

 

I concur....GAH?!

 

 

 

let my brain now be in a state of atrophy....

 

 

 

 

 

*sighs of relief*

You can't ever find a place that's nice and peaceful, because there isn't any. You may think there is, but once you get there, when you're not looking, somebody'll sneak up and write "(bleep) you" right under your nose. Try it sometime. I think, even, if I ever die, and they stick me in a cemetery, and I have a tombstone and all, it'll say "Holden Caulfield" on it, and then what year I was born and what year I died, and then right under that it'll say "(bleep) you."

 

 

 

Pwned.

 

 

 

 

 

 

 

You win :(.

I'm Jake Milroy

interesting..............................but i must add....GAH! :shock: there we go!

dmanxb7.jpg

Trix.--quit WoW as of 12/07

Thank you 4be2jue for the wonderful sig and avatar!

ooo i remember one of my teachers teaching us this... it was interesting, i forgot how he proved it though. he said in math, most people accept the fact that .9 repeating = 1.

Also, if you think about it, what would you add to .9 repeated to get 1? It would have to be .0 repeated but where would you add the 1 inside of the .0 repeated?

 

 

 

No..you add .1111... to .9999.. to get 1. Ya'll are all thinking way too into this.

 

.9999 and 1 are not equal. No matter how infinitely small the difference may be there is still a difference. And no 1/3 + 2/3 does not equal .999.. it equals to 3/3. Fractions and decimals are two totally different ways of viewing things. I think everyone is just thinking too deep into this. :lol: Or I could be an idiot in some parallel universe where numbers hold the world together :wall: lol

supdarklinkel1.jpg
Also, if you think about it, what would you add to .9 repeated to get 1? It would have to be .0 repeated but where would you add the 1 inside of the .0 repeated?

 

 

 

No..you add .1111... to .9999.. to get 1. Ya'll are all thinking way too into this.

 

.9999 and 1 are not equal. No matter how infinitely small the difference may be there is still a difference. And no 1/3 + 2/3 does not equal .999.. it equals to 3/3. Fractions and decimals are two totally different ways of viewing things. I think everyone is just thinking too deep into this. :lol: Or I could be an idiot in some parallel universe where numbers hold the world together :wall: lol

 

Eh? .1111 repeating + .9999 repeating does not equal 1... Learn your mathematics...

  • Author
Also, if you think about it, what would you add to .9 repeated to get 1? It would have to be .0 repeated but where would you add the 1 inside of the .0 repeated?

 

 

 

No..you add .1111... to .9999.. to get 1. Ya'll are all thinking way too into this.

 

.9999 and 1 are not equal. No matter how infinitely small the difference may be there is still a difference. And no 1/3 + 2/3 does not equal .999.. it equals to 3/3. Fractions and decimals are two totally different ways of viewing things. I think everyone is just thinking too deep into this. :lol: Or I could be an idiot in some parallel universe where numbers hold the world together :wall: lol

 

 

 

.1... + .9... = 1.1... NOT 1.

 

 

 

1/3 is equal to .3... meaning it should be interchangable.

 

 

 

Let 1/3 = x

 

Let .3... = y

 

 

 

3x = 1

 

3y = .99999...

 

 

 

So that's the question .999999... =? 1

 

 

 

I think it's to late for you to be thinking correctly. Or what you said at the end.

 

 

 

 

 

In order to get 1 from .9999... you would need to add an infinite amount of zeros with a 1 at the very very end of infinite which ends no where.

1z2zrwo.jpg

GAH?! :shock:

 

 

 

well, i can't figure that out, right now i have ems (early morning syndrome) well i dont know this answer but i know this.........Chicken Nuggets own u

I Feel The Exact Same Way #-o

  • Author
Why didn't you carry the n on the -9/-9 (first code below the line)?

 

 

 

you need to try to get n = fraction

 

 

 

So you divide 9 on both sides to get n alone.

 

 

 

Well I'm not really sure what you're saying but I think that was it.

1z2zrwo.jpg

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